Any help would be appreciated!
solve for y
y=18.5+6sin((9(pi/12)) - (10(pi/12)))
+118696 I am jut going to REDO it here :))
y=18.5+6sin((9(π/12))−(10(π/12)))y=18.5+6sin(9π/12−10π/12)))y=18.5+6sin(−π/12)))$4thquadsoneg$y=18.5−6sin(π/12)))y=18.5−6sin(150)y=18.5−6sin(45−30)y=18.5−6[sin45cos30−cos45sin30]y=18.5−6[1√2∗√32−1√2∗12]
y=18.5−6[√32√2−12√2]y=18.5−6[√64−√24]y=18.5−3[√62−√22]y=37−3√6+3√22
Ok NOW our answers are the same :))
+118696 Thiere is a mistake in this one so you had best ignore it ://
y=18.5+6sin((9(π/12))−(10(π/12)))y=18.5+6sin(3π/4)−(5π/6)y=18.5+6sin(3π/4)−(5π/6)$secondquadsothesineispositive$y=18.5+6sin(π−\3pi/4)−(5π/6)y=18.5+6sin(π/4)−(5π/6)y=18.5+6∗1√2−(5π/6)y=18.5+6∗1∗√2√2∗√2−(5π/6)y=18.5+6∗√22−(5π/6)y=18.5+3√2−5π6
Hello,melody and anon!
I think melody made a mistake.（9pi/12-10pi/12 is in inside of the parentheses)
y=18.5+6sin((9(pi/12)) - (10(pi/12)))
y=18.5+6sin(9pi/12-10pi/12)
y=18.5+6sin(-pi/12)
y=18.5-6sin(pi/12)
y=18.5-6sin(pi/4-pi/6)
y=18.5−6×(sin360∘(π4)×cos360∘(π6)−cos360∘(π4)×sin360∘(π6))
sin360∘(π4)=√22 cos360∘(π6)=√32 cos360∘(π4)=√22 sin360∘(π6)=12
y=18.5−6×(√64−√24)=18.5−3×√62+3×√22
+118696 I am jut going to REDO it here :))
y=18.5+6sin((9(π/12))−(10(π/12)))y=18.5+6sin(9π/12−10π/12)))y=18.5+6sin(−π/12)))$4thquadsoneg$y=18.5−6sin(π/12)))y=18.5−6sin(150)y=18.5−6sin(45−30)y=18.5−6[sin45cos30−cos45sin30]y=18.5−6[1√2∗√32−1√2∗12]
y=18.5−6[√32√2−12√2]y=18.5−6[√64−√24]y=18.5−3[√62−√22]y=37−3√6+3√22
Ok NOW our answers are the same :))
