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Any help would be appreciated!

solve for y

y=18.5+6sin((9(pi/12)) - (10(pi/12)))

 Aug 16, 2015

Best Answer 

 #4
avatar+118696 
+10

I am jut going to REDO it here   :))

 

y=18.5+6sin((9(π/12))(10(π/12)))y=18.5+6sin(9π/1210π/12)))y=18.5+6sin(π/12)))$4thquadsoneg$y=18.56sin(π/12)))y=18.56sin(150)y=18.56sin(4530)y=18.56[sin45cos30cos45sin30]y=18.56[12321212]

 

y=18.56[322122]y=18.56[6424]y=18.53[6222]y=3736+322

 

Ok NOW our answers are the same :))

 Aug 16, 2015
 #1
avatar+118696 
+5

Thiere is a mistake in this one so you had best ignore it ://

 

y=18.5+6sin((9(π/12))(10(π/12)))y=18.5+6sin(3π/4)(5π/6)y=18.5+6sin(3π/4)(5π/6)$secondquadsothesineispositive$y=18.5+6sin(π\3pi/4)(5π/6)y=18.5+6sin(π/4)(5π/6)y=18.5+612(5π/6)y=18.5+61222(5π/6)y=18.5+622(5π/6)y=18.5+325π6

 Aug 16, 2015
 #2
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+10

Hello,melody and anon!

I think melody made a mistake.(9pi/12-10pi/12 is in inside of the parentheses)

 y=18.5+6sin((9(pi/12)) - (10(pi/12)))

y=18.5+6sin(9pi/12-10pi/12)

y=18.5+6sin(-pi/12)

y=18.5-6sin(pi/12)

y=18.5-6sin(pi/4-pi/6)

y=18.56×(sin360(π4)×cos360(π6)cos360(π4)×sin360(π6))

sin360(π4)=22  cos360(π6)=32 cos360(π4)=22 sin360(π6)=12

y=18.56×(6424)=18.53×62+3×22

 Aug 16, 2015
 #3
avatar+118696 
0

Yes you are right. Thanks for noticing that :)

 Sorry anon  :/

 Aug 16, 2015
 #4
avatar+118696 
+10
Best Answer

I am jut going to REDO it here   :))

 

y=18.5+6sin((9(π/12))(10(π/12)))y=18.5+6sin(9π/1210π/12)))y=18.5+6sin(π/12)))$4thquadsoneg$y=18.56sin(π/12)))y=18.56sin(150)y=18.56sin(4530)y=18.56[sin45cos30cos45sin30]y=18.56[12321212]

 

y=18.56[322122]y=18.56[6424]y=18.53[6222]y=3736+322

 

Ok NOW our answers are the same :))

Melody Aug 16, 2015

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