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Vertex form of a parabola :
y = a(x-h)^2 +k
First one: y = a (x-4)^2 -2 You are given a convenient point on the parabola to find 'a'
Let's sub 7,3 into the equation
3 = a (7-4)^2 -2 solve for a = 5/9
y = 5/9 (x-4)^2 -2