What is the y-coordinate of the point on the y-axis that is equidistant from points (-2, 0) and (-1, 4)?
Im getting 13/8.
(-2)^2+y^2=4+y^2=x^2
(-1)^2+(y-4)^2=1+y^2+16-8y=x^2.
4+y^2=y^2+1+16-8y
8y=13
y=$\boxed{\frac{13}8}$
+591 
