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What is the y-coordinate of the point on the y-axis that is equidistant from points (-2, 0) and (-1, 4)?

 Mar 3, 2021
 #1
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Im getting 13/8.

 Mar 3, 2021
 #2
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(-2)^2+y^2=4+y^2=x^2

(-1)^2+(y-4)^2=1+y^2+16-8y=x^2.  

4+y^2=y^2+1+16-8y

8y=13

y=$\boxed{\frac{13}8}$

 Mar 3, 2021
edited by SparklingWater2  Mar 3, 2021

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