The probability of a potential employee passing a training course is 86%. If you selected 15 potential employees and gave them the training course, what is the probability that 11 or less will pass the test?

Guest Jan 19, 2020

#1**0 **

This is a binomial distribution: one formula for solving this problem is:

_{15}C_{11}·(.86)^{11}·(.14)^{4} + _{15}C_{10}·(.86)^{10}·(.14)^{5} + _{15}C_{9}·(.86)^{9}·(.14)^{6} + ... + _{15}C_{1}·(.86)^{1}·(.14)^{1}^{4} + _{15}C_{0}·(.86)^{0}·(.14)^{15}

I'll let you calculate this (there is a simpler way).

geno3141 Jan 20, 2020