The probability of a potential employee passing a training course is 86%. If you selected 15 potential employees and gave them the training course, what is the probability that 11 or less will pass the test?
This is a binomial distribution: one formula for solving this problem is:
15C11·(.86)11·(.14)4 + 15C10·(.86)10·(.14)5 + 15C9·(.86)9·(.14)6 + ... + 15C1·(.86)1·(.14)14 + 15C0·(.86)0·(.14)15
I'll let you calculate this (there is a simpler way).
