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A snail fell into a well which is 3 m deep. It would climb 1/4 m up the all in the day and slide 1/10 m in the night. How many days would the snail take to get out of the well?

 Aug 12, 2021
edited by mitgliedd1  Aug 12, 2021
 #1
avatar+121064 
+1

Each  day.....the snail   gains      (1/4   -1/10)m    = (.25 - .10),  =   .15m

 

So.....the  number of days  to  reach   the  top  =   3/.15  =   20 days

 

So....the  snail gets out  of the  well  on the 21st   day.....!!!!

 

 

cool cool cool

 Aug 12, 2021
 #2
avatar+62 
+1

Hi Guest,

 

Total is 3m

 

Climb 1/4x, then -  1/10x

 

3 = 1/4x - 1/10x

 

10/40 - 4/40 = 6/40 = 3/20x

 

3/20x = 3

 

x = 20

 

It would take 20 days for snail to get out of well.

 Aug 12, 2021

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