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arccos(cos230)

 Nov 19, 2015

Best Answer 

 #1
avatar+118724 
+10

assuming degrees

 

arccos(cos230)

=arccos(-cos(230-180))

=arccos(-cos(50))

=arccos(cos(180-50))

=arccos(cos(130))

=130 degrees

 Nov 19, 2015
 #1
avatar+118724 
+10
Best Answer

assuming degrees

 

arccos(cos230)

=arccos(-cos(230-180))

=arccos(-cos(50))

=arccos(cos(180-50))

=arccos(cos(130))

=130 degrees

Melody Nov 19, 2015
 #2
avatar
+5

thank you

 Nov 19, 2015
 #3
avatar+118724 
0

Do you have any questions?  :)

 Nov 19, 2015

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