i have 8 pieces of lemon candy and 7 pieces of watermelon candy. in how many ways can i distribute this candy to four students
First, notice that if all the candies were different, it would simply be 4^15 (4 possible kids for each candy). If all the candies were the same, it would be (4 multichoose 15). This problem is something in between.
The answer is (4 multichoose 8) * (4 multichoose 7) = C(11,8)*C(10,7) = C(11,3)*C(10,3) = 19800
+118609 i have 8 pieces of lemon candy and 7 pieces of watermelon candy. in how many ways can i distribute this candy to four students
Assuming each student is counted as and individual then I think
(8+4-1)C3 * (7+4-1)C3
=11C3 * 10C3
=165 * 120
=19,800
I did mine using stars and bars method.
Our answers are the same which is a good sign but they could both be wrong.
