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i have 8 pieces of lemon candy and 7 pieces of watermelon candy. in how many ways can i distribute this candy to four students

 Dec 30, 2019
 #1
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First, notice that if all the candies were different, it would simply be 4^15 (4 possible kids for each candy). If all the candies were the same, it would be (4 multichoose 15). This problem is something in between.

The answer is (4 multichoose 8) * (4 multichoose 7) = C(11,8)*C(10,7) = C(11,3)*C(10,3) = 19800

 Dec 30, 2019
 #2
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i have 8 pieces of lemon candy and 7 pieces of watermelon candy. in how many ways can i distribute this candy to four students

 

Assuming each student is counted as and individual then I think

 

(8+4-1)C3  *  (7+4-1)C3 

=11C3          *       10C3

=165            *          120

=19,800

 

I did mine using stars and bars method.

 

Our answers are the same which is a good sign but they could both be wrong.

 Dec 31, 2019

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