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Andrew and Caden had some stamps in the ratio 6:8. Andrew gave a quarter of his stamps to Caden. Caden then had 280 stamps more than Andrew. How many stamps did they have altogether?

 Jul 13, 2024
 #1
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We can wrte down 2 equations for this then use substitution to solve it.

 

\(6a=8c\)

\(\frac{3}{4}a+280=c+\frac{1}{4}a\)

 

 

\(\frac{3}{4}a=c\)

\(c+280=c+\frac{1}{4}a\)

\(\frac{1}{4}a=280\)

\(a=1120\)

\(\frac{3}{4}(1120)=c\)

\(c=840\)

 

 

Let's double check:

 

\(6(1120)=8(840)\)

\(6720=6720\)

 

\(\frac{3}{4}(1120)+280=840+\frac{1}{4}(1120)\)

\(840+280=840+280\)

\(1120=1120\)

 

 

So both equations are true, therefore, Andrew has 1120 stamps and Caden has 840 stamps.

 Jul 13, 2024

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