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Let △ABC and △CDE be equilateral triangles of the same size, and ∠BCD=80∘ between them. Find the measure of ∠BAD in degrees.

Guest Jun 29, 2020

Bosco · Answer 1 · 2026-01-30T04:32:30

angle ACB = 60^o therefore angle ACD is (60^o + 80^o) = 140^o

side AC = side CD making triangle ACD isoceles

angle CAD = angle angle CDA, so each is (1/2)(180^o –140^o) = 20^o

angle BAD = (60^o – 20^o) = 40^o

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