help

You mean as in solving for x, right?

Let's solve your equation step-by-step.

x^2−5x−12=0

For this equation: a=1, b=-5, c=-12

1x^2+(−5x)+(−12)=0

Step 1: Use quadratic formula with a=1, b=-5, c=-12.

x=−b±√b^2−4ac / 2a

x= −(−5)±√(−5)2−4(1)(−12) / 2(1)

x= 5±√73 / 2

so, 

x=5/2+ 1/2 √73 

or

 x= 5/2 + (−1)/2 √73

the / symbol means that it is a fraction.