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Jeremiah has $2.10 worth of nickels and dimes. He has a total of 30 nickels and dimes altogether. Determine the number of nickels, x, and the number of dimes, y, that Jeremiah has.

 Mar 21, 2020
 #1
avatar+1970 
+2

We can write two equations for this...

 

Where d=number of dimes and n=number of nickels.. In cents the equation will be:

 

10d+5n=210

d+n=30

 

We can use the elimination method to get

10d+5n=210

10d+10n=300

Then subtract.

 

-5n=-90.

 

So the number of nickels is 18.

That makes the number of dimes 12.

 Mar 21, 2020
edited by CalTheGreat  Mar 21, 2020
 #2
avatar+108 
+2

In total, he has 210 cents

n + d = 30

5n + 10d = 210

multiply 5 to the first equation

then minus the first from the second one

you get 60 = 5d

12 dimes or 12 y

and 

18 nickels or 18 x

 Mar 21, 2020
 #3
avatar+111330 
0

Thanks, brian  and CTG    !!!!

 

cool cool cool

 Mar 21, 2020

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