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Engineers use the formula $L=\frac{25T^4}{H^2}$ to find the crushing load for square pillars. If $T = 4$ and $H = 8$, what is the value of $L$?

 Jul 23, 2019
 #1
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L = 25 T^4 /  H^2

L = 25 (4^4) / (8^2)

L = 25 *4^4/(8^2) = 100        I do not know what the units are....You should be able to do these problems...all of the variables are given...just plug and play.

 Jul 23, 2019
 #2
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Guest asker,

Since you are too lazy to delete the dollar signs and make your question readable I do not think you should bother enrolling in engineering.

I do not want to enter any building you design.  No Earthquake will be needed to induce that disaster.

 Jul 23, 2019
 #3
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cheeky   THAT is funny!   I agree.....seems asker is in a bit over her/his head with this level of math !   ~EP

ElectricPavlov  Jul 23, 2019

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