\(\begin{align} x+x+y&=14\\ L+L+z&=20\\ x+y+z&=12\\ x+z+L&=18 \end{align}\)
If numbers x,y,z,L satisfy the equations above, find the value of x+z
+36915 From the first equation 2x+ y = 14 y = 14-2x
From the second equation L = 10- 1/2 z
Add 3rd and 4th 2x + 2z + y + L = 30 sub in the above 2 equations
2x + 2z + 14-2x + 10 - 1/2z = 30 simplify
1 1/2 z + 24 = 30
z = 4
From third equtiion x + 14-2x + 4 = 12
-x = -6 x = 6 x + z = 10
