All vertices of pentagon ABCDE lie on a circle. We know that AB = BC = CD = DE and angle ABC = 128. Find angle ACE in degrees.
+532 i dont know how to solve this, but i think a way to make it easier is to draw all the diagonals
+128408 Just a rough pic for reference......definitely not exact!!!!
A
E B
D
C
Since ABC = 128°.......then major arc CA is twice 128° = 256°
Therefore.......arc ABC = 360° - 256° = 104°
But.....since AB = BC....then each of these chords must span an arc of 52°
And since AB = BC = CD = DE.....these equal chords each span an arc of 52°
So....arc EA must be 360 - 4(52) = 152°
And angle ACE is an inscrbed angle subtending EA....so it's measure is (1/2) measure arc EA = 76°
