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How many four-digit positive integers are multiples of 3? 

 Jan 7, 2019
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[L - F] / D + 1 = N, where L = Last term, F = First term, D = Common difference, N = Number of terms

[9,999 - 1,002] / 3 + 1 = 3,000 - 4-digit numbers that are multiples of 3.

 Jan 7, 2019
edited by Guest  Jan 7, 2019

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