+0  
 
0
730
2
avatar+492 

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 Jan 14, 2017

Best Answer 

 #2
avatar+101 
+10

when we have the coordinates of two points, and that we want to calculate the distance between them, we do the following: 

1-calculate the victor that links the two points ( in this case MZ )

2-we calcutate the magnitude of the vector MZ 

\(MZ= \begin{pmatrix} -1-6\\ 14-16 \end{pmatrix} = \begin{pmatrix} -7\\ -2 \end{pmatrix}\) this is the vector MZ 

Now its magnitude:

\(MZ = \sqrt{(-7)²+(-2)²}=\sqrt{53} = 7.2801..=7.3\)

 Jan 14, 2017
 #1
avatar+129899 
+5

d = √ [ -1 - 6)^2  + ( 16 - 14 )^2 ]  =  √ [ ( - 7)^2  + ( 2 )^2 ]  = √  [49 + 4] = √ 53  ≈  7.3

 

 

cool cool cool

 Jan 14, 2017
 #2
avatar+101 
+10
Best Answer

when we have the coordinates of two points, and that we want to calculate the distance between them, we do the following: 

1-calculate the victor that links the two points ( in this case MZ )

2-we calcutate the magnitude of the vector MZ 

\(MZ= \begin{pmatrix} -1-6\\ 14-16 \end{pmatrix} = \begin{pmatrix} -7\\ -2 \end{pmatrix}\) this is the vector MZ 

Now its magnitude:

\(MZ = \sqrt{(-7)²+(-2)²}=\sqrt{53} = 7.2801..=7.3\)

Majid Jan 14, 2017

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