The perimeter of the larger rectangle is 2 meters greater than twice the perimeter of the smaller rectangle. What is the perimeter of the larger rectangle?
Perimeter = 2 ( W + L) .....so....
We have that
2 [ (x + 1) + x ] + 2 = 2 [(3x - 1) + (4x - 5) ] simplify
2 [ 2x + 1 ] + 2 = 2 [ 7x - 6]
4x + 2 + 2 = 14x - 12
4x + 4 = 14x - 12 add 12 to both sides, subtract 4x from both sides
16 = 10x divide both sides by 12
16/10 = x = 8/5
Perimeter of larger rectangle = 14(8/5) -12 = (112 - 60)/5 = 52/ 5 = 10.4 m