Rhombus $ABCD$ has perimeter $148$, and one of its diagonals has length $24$. How long is the other diagonal?
Well let us name the side lengths $x$
$4x=148$
$x=37$ we know a side of diagonal, divide it by 2 and it is 12, by the Pythagorean theorem
12^2+(y^2)=37^2
y^2=1225
$y=35$
thereofre the other length of the diagonal is 35*2=$70$
Thank you!
+82 
