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Rhombus $ABCD$ has perimeter $148$, and one of its diagonals has length $24$. How long is the other diagonal?

 Jan 8, 2021
 #1
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Well let us name the side lengths $x$

$4x=148$

$x=37$
we know a side of diagonal, divide it by 2 and it is 12, by the Pythagorean theorem

12^2+(y^2)=37^2

y^2=1225

$y=35$

thereofre the other length of the diagonal is 35*2=$70$

 Jan 8, 2021
 #2
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Thank you!

Leafie  Jan 15, 2021

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