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A certain television is advertised as a 113-inch TV (the diagonal length). If the width of the TV is 112 inches, how many inches tall is the TV?

 Nov 5, 2018
edited by Guest  Nov 5, 2018

Best Answer 

 #1
avatar+17332 
+3

Pythagorean theorom again

a^2 + b^2 = c^2

Hypotenuse is the diagonal measure of 113

One leg is 112

 a^2 + 112^2 = 113^2

a^2 = 113^2 - 112^2

a = 15 in

 Nov 5, 2018
 #1
avatar+17332 
+3
Best Answer

Pythagorean theorom again

a^2 + b^2 = c^2

Hypotenuse is the diagonal measure of 113

One leg is 112

 a^2 + 112^2 = 113^2

a^2 = 113^2 - 112^2

a = 15 in

ElectricPavlov Nov 5, 2018
 #2
avatar+3994 
+1

Good job, EP! Note that from here, a^2=113^2-112^2, we can just add 113 and 112, because they are consecutive squares. So, a^2=225, a=15 inches.

 Nov 5, 2018

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