In this problem, m and n are integers. If \(m\equiv 4\pmod{14}\) and \(m-n\equiv 10\pmod{14}\), then what is the remainder when m+n is divided by 14?
m mod 14 = 4,
(m - n) mod 14 =10, solve for m, n
m = 14 c + 4 and n = 14 d + 8, So:
m =4 and n = 8
[4 + 8] mod 14 ==12
