On an old-fashioned bicycle the front wheel has a radius of 2.5 feet and the back wheel has a radius of 4 inches. If there is no slippage, how many revolutions will the back wheel make while the front wheel makes 100 revolutions?

Lightning Dec 24, 2018

#1**+2 **

Converting feet to inches, we have 2.5*12=30 inches. This is for the front wheel, while the back wheel's radius is 4 inches. Revolutions come hand in hand with the circumference, so we have 2*30*pi=60pi for the front wheel and 2*4*pi=8pi for the back wheel. Now, when 60pi=100 then by indirect proportion \(\frac{60*100}{8}=\boxed{750} \) revolutions.

tertre Dec 24, 2018

#2**+2 **

Note : 2.5 ft = 30 in

When the front wheel makes 100 revs, the bike will travel (in inches)

100 * 2pi * 30 = 6000pi in

So....the number of revs that the back wheel makes is

Total distance traveled / distance traveled in one rev by back wheel =

[ 6000 pi ] / [ 2pi * 4 ] = 6000/8 = 750 revolutions

CPhill Dec 24, 2018