The average of 19 consecutive integers is 99. What is the largest of these integers?
19 integers, with one in the middle being 99.
Before 99, there is 98, 97, 96 . . . 90.
After 99, there is 100, 101, 102 . . . 108.
This is because the average of 98 and 100 is 99, and so is every other pair.
I dont even know what I'm sayin, anyways, 108 is the largest integer this problem is too easy to explain.