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The average of 19 consecutive integers is 99. What is the largest of these integers?

 Jun 5, 2020
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avatar+107 
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19 integers, with one in the middle being 99.

Before 99, there is 98, 97, 96 . . . 90. 

After 99, there is 100, 101, 102 . . . 108.

This is because the average of 98 and 100 is 99, and so is every other pair.

I dont even know what I'm sayin, anyways, 108 is the largest integer this problem is too easy to explain.

 Jun 5, 2020

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