#1**0 **

*With each stroke, a pump removes 2/5 of the air in a container. *

*After 3 strokes, what is the fraction of the original amount of air in the container that is left.*

Call "x" the original amount of air in the container.

After the 1st stroke, (2/5) of x has been removed ... 3/5 of x is left.

After the 2nd stroke, (2/5) • (3/5) of x has been removed

(2/5) • (3/5) = 6/25 removed .... 19/25 of x is left.

After the 3rd stroke, (2/5) • (19/25) of x has been removed

(2/5) • (19/25) = 38/125 removed ... **87/125** of x is left.

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Bosco Oct 26, 2024