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A lot of laptop computers contain 20 good ones and 3 defective ones. If two are selected and tested, find the probability that at least one will be defective.

 Mar 19, 2020
 #1
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+1

P(at least  one defective laptop)  =

 

1 - P(neither laptop is  defective)  = 

 

1  - (20/23)(19/22)   =   

 

63/253 ≈  .249  ≈  24.9%

 

 

cool cool cool

 Mar 19, 2020

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