+0  
 
0
96
1
avatar

triangle side=

a=130mm

b=96.8mm

c=56mm

a)what is the angle abc

Guest Jan 28, 2018
 #1
avatar+86859 
+1

We can use the Law of Cosines to solve this

 

We have that

 

96.8^2  = 130^2  + 56^2  - 2(130)(56)cos(ABC)       rearrange as

 

[ 96.8^2 - 130^2 - 56^2 ] / [ -2(130)(56)]  =  cos(ABC)

 

Using the cosine inverse (arccos), we have

 

arccos ( [ 96.8^2 - 130^2 - 56^2 ] / [ -2(130)(56)] )  = ABC ≈  42.9°

 

 

cool cool cool

CPhill  Jan 28, 2018

7 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.