The domain of the function r(x) = \(\frac{x^2}{1-x}\) is (-inf,1) U (1,inf). What is the range?

My answer was (-inf, -4,] U [0, inf), but that's apparently wrong. what did i do wrong?

atlas9 Feb 2, 2020

#1**+2 **

As you approach from - inf to 1 the range goes from +inf to a MINIMM of 0 (at x=0) and then back to + inf

on the other side of 1 it goes from - inf to a MAXIMUM of -4 at x = 2 and then to - inf

(+inf, 0 ] U (-inf, -4] which I think is what you have.....maybe the order is incorrect for the software answer?

ElectricPavlov Feb 3, 2020