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The domain of the function r(x) = \(\frac{x^2}{1-x}\) is (-inf,1) U (1,inf). What is the range?

 

My answer was (-inf, -4,] U [0, inf), but that's apparently wrong. what did i do wrong?

 Feb 2, 2020
 #1
avatar+22080 
+2

As you approach from - inf to 1      the range goes from +inf   to a MINIMM of 0   (at x=0)  and then back to + inf

    on the other side of 1    it goes from - inf to a MAXIMUM of -4   at x = 2   and then to - inf

 

(+inf, 0 ]  U  (-inf, -4]        which I think is what you have.....maybe the order is incorrect for the software answer?   

 Feb 3, 2020
edited by ElectricPavlov  Feb 3, 2020

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