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Suppose k is a positive integer such that 6k has exactly 9 positive divisors.

What is k?

Forumofweb2.0cal May 29, 2020

2⁺¹ Answers

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$6n = 36$

_{positive divisors:}

$1, 2, 3, 4, 6, 9, 12, 18,36$

_therefore:

$n = 6$

Hephaestus May 29, 2020

+174

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Thank You!

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