Solve for x:

4^2x * 1/16 = 4^(6x+18)

I've been stuck on this question for a while now. I need to make it have a common side then work for x but I'm confused. I would upload a picture but it's not working for some reason. Please show work because I need to understand. Thanks.

Guest Aug 9, 2019

#1**+1 **

I'm assuming this is :

4^(2x) * 1/16 = 4^(6x+18)

Note that 1/16 = 1 / 4^2 = 4^(-2) ....so we have

4^(2x) * 4^(-2) = 4^(6x + 18) using a property of exponents, we can write

4^(2x -2) = 4^(6x + 18) we have the bases the same.....we can solve for the exponents

2x - 2 = 6x + 18 add 2 to both sides....subtract 6x from both sides

-4x = 20 divide both sides by -4

x = -5

CPhill Aug 9, 2019