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Solve for x:

4^2x * 1/16 = 4^(6x+18)

 

I've been stuck on this question for a while now. I need to make it have a common side then work for x but I'm confused. I would upload a picture but it's not working for some reason. Please show work because I need to understand. Thanks.

 Aug 9, 2019
 #1
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I'm assuming this is : 

 

4^(2x) * 1/16 = 4^(6x+18)

 

Note that 1/16  =   1 / 4^2 =    4^(-2)   ....so we have

 

4^(2x) * 4^(-2)  = 4^(6x + 18)           using a property of  exponents, we can write

 

4^(2x  -2)  = 4^(6x + 18)        we have the  bases the  same.....we can solve  for the  exponents

 

2x  - 2 =  6x  + 18       add 2 to both sides....subtract 6x from both  sides

 

-4x = 20      divide both sides  by  -4

 

x  = -5

 

 

cool cool cool

 Aug 9, 2019

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