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Given an arithmetic sequence {an} such that an = 179 and an+4m = 663. Find an+3m.

Guest May 29, 2016

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Best Answer

+23251

+10

If an = 179 and an + 4m = 663

then: 179 + 4m = 663

and: 4m = 484

and: m = 121

Thus: an + 3m = 179 + 3·121 = 179 + 363 = 542

geno3141 May 29, 2016

1⁺⁰ Answers

+23251

+10

Best Answer

If an = 179 and an + 4m = 663

then: 179 + 4m = 663

and: 4m = 484

and: m = 121

Thus: an + 3m = 179 + 3·121 = 179 + 363 = 542

geno3141 May 29, 2016

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