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Help.

 Dec 8, 2017
 #1
avatar+128407 
+1

The zeros are  -5/2   ,  1/2   and 3/2

 

So....to get the correct factors...  write each denominator as the first term in each factor and change the sign on the numerator as the second term in each.... so...we must have had     

(2x + 5) (2x - 1) (2x - 3)  = 0

 

The first answer

 

 

cool cool cool

 Dec 8, 2017

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