how to solve:
show that for small angles under 20º that
tan a ≈ sin a≈ a≈ pi *a` /180º
also find largest angle for which tan a may be approximated by sin a if error is less than 10.0%
a is radians and a` is degrees
thanks
Well tan a = sina / cosa for small angles cosa ~ 1 thus tana = ~ sina /1 = sin a
.9 tana = sina
tana / sina = 1/ .9
1/cosa = 1/.9
.9 = cosa a =25.84 degrees Tan 25.84 = .484 sin 25.84 = .4358
Show that for small angles under 20º that tan a ≈ sin a?
Construct a right-angled triangle with angle theta and 3 side lengths = a,b, and c.
Just like this:
As theta decreases, sin theta=b/c decreases, therefore b decreases, therefore cos theta approaches 1, therefore a ≈ c, therefore b/a ≈ b/c, therefore tan theta ≈ sin theta.
For sin a ≈ a part.....
Use my triangle above.
As theta approaches 0, b approaches 0, b/c approaches 0, therefore sin theta approaches 0
This can be represented as \(\displaystyle\lim_{\theta\rightarrow0}\sin \theta=0\)
Therefore for small values, sin a ≈ a