A sculpture is to include 12 suspended identical tubes. The tubes are regular hexagonal prisms. The tubes have very thin walls and are open at each end. Each tube is

11 ft

long with edges that are each

4 ft.

The sculptor wants to paint the inside and outside of each tube. A can of paint covers

40 ft squared

How many cans of paint does the sculptor need?

Guest May 7, 2020

#1**0 **

Each side of each tube is a rectangle 4 ft x 11 ft = 44 ft^{2}.

Since both the inside and outside are to be painted, each side = 88 ft^{2}.

Since each tube is hexagonal: 88 ft^{2} x 6 = 528 ft^{2}.

Since there are 12 tubes: 528 ft^{2} x 12 = 6336 ft^{2}.

Since each can of point covers 40 ft^{2}: 6366 ft^{2} / 40 ft^{2} = 158.4 cans ---> 159 cans.

geno3141 May 7, 2020