A sculpture is to include 12 suspended identical tubes. The tubes are regular hexagonal prisms. The tubes have very thin walls and are open at each end. Each tube is
11 ft
long with edges that are each
4 ft.
The sculptor wants to paint the inside and outside of each tube. A can of paint covers
40 ft squared
How many cans of paint does the sculptor need?
+23246 Each side of each tube is a rectangle 4 ft x 11 ft = 44 ft2.
Since both the inside and outside are to be painted, each side = 88 ft2.
Since each tube is hexagonal: 88 ft2 x 6 = 528 ft2.
Since there are 12 tubes: 528 ft2 x 12 = 6336 ft2.
Since each can of point covers 40 ft2: 6366 ft2 / 40 ft2 = 158.4 cans ---> 159 cans.
