+118654
Help for domain please
\(log_2(x^2-5x)\le log_2(6x+12)\\ 2^{log_2(x^2-5x)}\le 2^{log_2(6x+12)}\\ x^2-5x\le 6x+12\\ x^2-5x-6x-12\le 0\\ x^2-11x-12\le 0\\ (x-12)(x+1)\le0\\ \text{Now graph or think about the graph of } y=(x-12)(x+1)\\ \text{The equality is true where } y \le 0\\ \text{This means the equality will be true for all x where the y value is under the x axis.}\)
Now
y=(x-12)(x+1)
This is a concave up parabola which has x intercepts at x=12 and x=-1
so it will be under the x axis between these values
so
\(-1\le x\le12\)
If you need further explanation then ask for it :)
