(2a−5)x^2−2(a−1)x+3=0
Let b = -2(a - 1) = 2 - 2a
Let a = (2a - 5)
Let c = 3
This will happen when
b^2 - 4ac = 0 ....so we have.....
(2 - 2a)^2 - 4(2a - 5)(3) = 0 simplify
4a^2 - 8a + 4 - 24a + 60 = 0
4a^2 - 32a + 64 = 0
a^2 - 8a + 16 = 0
(a - 4)^2 = 0
And a = 4
