+118724 6/((-i(sqrt(3))/2)
I have assumed that \(i=\sqrt{-1}\)
\(6\div ((-\sqrt3 i)/2)\\ =6\div \frac{-\sqrt3 i}{2}\\ =-6\times \frac{2}{\sqrt3 i}\\ = \frac{-12}{\sqrt3\; i}\\ = \frac{-12}{\sqrt3\; i}\times\frac{\sqrt3\;i}{\sqrt3\;i}\\ = \frac{-12\sqrt3\;i}{3*-1}\\ = \frac{4\sqrt3\;i}{1}\\ =4\sqrt3\;i \)
