The conjugate of [ sqrt(3) -1 ] is [ sqrt(3) + 1 ]
Numerator: [ 6 + 10sqrt(3) ] · [ sqrt(3) + 1 ] = 6sqrt(3) + 6 + 10sqrt(3)sqrt(3) + 10sqrt(3)
= 6sqrt(3) + 6 + 10·3 + 10sqrt(3)
= 16sqrt(3) + 36
Denominator: [ sqrt(3) - 1 ] · [ sqrt(3) + 1 ] = 3 - 1 = 2
Answer = [ 16sqrt(3) + 36 ] / 2 = 8sqrt(3) + 18