A vertical pole AB measuring 5 meters snaps at point C. The pole remains in contact at C and the top of the pole touches the ground at point T, a distance of 3 meters from A. Find the length AC, in meters, the point where the pole snapped.
Call the distance from A to C =x The distance from C to T = 5 - x, which is the hypotenuse of a right triangle. (5 - x)^2 = x^2 + 3^2, solve for x x =AC =8/5 =1 3/5 meters.
