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Find the set of values \(a\) for which the range of the function \(f(x) = \frac{x^2 + a}{x + 1}\) is the set of all real numbers.

 Aug 24, 2020
edited by Guest  Aug 24, 2020
 #1
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The set of possible values of a is [-2,2].

 Aug 24, 2020
 #2
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that's incorrect.

Guest Aug 24, 2020

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