Let a, b, and c be constants, and suppose that the inequality ((x-a)(x-b))/(x-c) <= 0 is true if and only if either x < -4 or |x-25| <= 1. Given that a < b, find the value of a + 2b + 3c.
<= mean less than or equal to
a = -3, b = 3, c = 5, so a + 2b + 3c = (-3) + 2*(3) + 3(5) = 18.
