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write the equation of center on y=x and tangent to both axis of radius = 4

 Nov 9, 2019
 #1
avatar+105971 
0

Have you drawn this on a rough graph?  That is always a good place to start?

Have you done anything towards finding a solution?

 Nov 9, 2019
 #2
avatar+105971 
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I have hidden your other 2 questions for the moment.

Learn from this one and then try the others by yourself.

I will help you if you are prepared to help yourself.

Have you drawn that diagram jet?

 Nov 9, 2019
 #3
avatar+60 
+1

thanks ...... i solve yhe question 

 

(x-4)2+(y-4)2=4

is it right ?

shgg111  Nov 9, 2019
 #4
avatar+105971 
+1

almost

the formula is 

\((x-h)^2+(y-k)^2=r^2\qquad \text{where the centre is (h,k) and the radius is r}\\ \text{so can you spot your error?}\)

Melody  Nov 9, 2019
 #5
avatar+60 
+1

(x-4)2+(y-4)2=16

 

is it right now ? 

thanks 

shgg111  Nov 9, 2019
 #6
avatar+105971 
+1

Yes, now it is spot on!    laugh

Melody  Nov 9, 2019
 #7
avatar+60 
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thank you 

shgg111  Nov 9, 2019
 #8
avatar+105971 
0

You are very welcome

Melody  Nov 9, 2019

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