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avatar+107 

In the figure below, GRAH  is a rectangle, RA = 7 , and GA = 10. Determine AH.

 

[asy] size(4cm);void mra(pair u, pair v, pair w, real r){ draw(v+(u-v)/length(u-v)*r--v+(u-v)/length(u-v)*r+(w-v)/length(w-v)*r--v+(w-v)/length(w-v)*r);} pair g=(0,7); pair h=(0,0); pair a=(sqrt(51),0); pair r=g+a;dot(g); dot(r); dot(a); dot(h);label(

 

PS. Even though I saw a post on this before, I tried their solution and it didn't work.

 Apr 1, 2019
 #1
avatar+1354 
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Alright, so first set up the equation a^2+b^2=c^2

In this equation AR equals a, so put 7 in for a. GA equals c, so put 10 in for c.

You get 7^2+b^2=10^2

From that you get 49+b^2=100

Minus 49 from both sides to get b^2=51

We know that the square root of 51 will be an irational number, so GR is the square root of 51.

You can solve it from there.

 Apr 1, 2019
 #2
avatar+107 
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Lol you gave me the answer! It was sqrt51 but thank you for helping me!

SoulSlayer615  Apr 1, 2019
 #3
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Thats what i mean by "solve from there"

 Apr 1, 2019

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