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Find all positive integers n, such that n/11 = the sum of the digits of n.

 

(One example of a number that works is 198, because the sum of the digits in 198 = 1+9+8 = 18, and 198/11 = 18.)

 May 30, 2020
 #1
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I had the computer search all the way up 10,000,000 numbers and it couldn't find any such numbers except the example you gave, i.e. 198. That seems to be the only number up to 10,000,000! Unless your Math Teacher wants you to go up the numberline to maybe a googol, or 10^100 !!?? But that would take forever, almost!.

 May 30, 2020
 #2
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It was only 198! Thanks for helping!

Guest May 30, 2020

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