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Solve(a^2+b^2)=c^2,c^2=3^2=?

nomnomers  Jul 23, 2017
 #1
avatar+87301 
+3

 

Solve(a^2+b^2)=c^2,c^2=3^2

 

So we have that

 

a^2 + b^2  = 3^2

 

a^2 + b^2   =  9

 

The solution is all the points (a,b)  that lie on a circle with a radius of 3

 

 

cool cool cool

CPhill  Jul 24, 2017
 #2
avatar+12 
0

No solve(a^2+b^2)=c^2,c^2=3^2={{a=r1, b=-sqrt(9-(r1^2)), c=-3, a=r2, b=sqrt(9-(r2^2)), c=-3}, {a=r3, b=-sqrt(9-(r3^2)), c=3, a=r4, b=sqrt(9-(r4^2)), c=3}}

nomnomers  Jul 24, 2017

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