Solve(a^2+b^2)=c^2,c^2=3^2=?
Solve(a^2+b^2)=c^2,c^2=3^2
So we have that
a^2 + b^2 = 3^2
a^2 + b^2 = 9
The solution is all the points (a,b) that lie on a circle with a radius of 3
No solve(a^2+b^2)=c^2,c^2=3^2={{a=r1, b=-sqrt(9-(r1^2)), c=-3, a=r2, b=sqrt(9-(r2^2)), c=-3}, {a=r3, b=-sqrt(9-(r3^2)), c=3, a=r4, b=sqrt(9-(r4^2)), c=3}}