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Compute \(\sum_{n = 2}^\infty \frac{4n^3 - n^2 - n + 1}{n^6 - n^5 + n^4 - n^3 + n^2 - n}.\)

 Feb 15, 2020
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∑[{4n^3 - n^2 - n + 1}{n^6 - n^5 + n^4 - n^3 + n^2 - n}, n, 2, infinity] =converges to 1

 Feb 15, 2020

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