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(1, 1)

(2, 4)

Let's see how ME got that answer

Set the equation equal

x^2   = 3x - 2      we can subtract 3x - 2 from both sides and we get

x^2 - 3x + 2   = 0      factor the left side

(x - 2) ( x - 1) = 0

Set each factor to 0  and solve for x and we get that

x =  2        and y = x^2    =   4

x = 1         and y = x^2   =    1

So....as ME found    (2, 4)   and ( 1, 1)