If sin A = 24/25 and 90 < A < 180, then find sin(A/2).
sin A = 24/25
cos A = - sqrt ( 1 - sin^2 A) = -sqrt ( 1 - 576/625) = - sqrt ( 625 - 576) / 25 = - sqrt ( 49) / 25 =
- 7/25
sin (A/ 2) = sqrt [ ( 1 - cos A) / 2 ] = √ ( 1 + 7/25)/ 2 ] = √ [ 32 / 50 ] = √ [ 16/25 ] = 4 / 5