A regular hexagon is divided into six congruent equilateral triangles. If the perimeter of one of the triangles is 39 inches, what is the perimeter of the regular hexagon, in inches?

Guest Nov 6, 2019

#1**+1 **

Since the regular hexagon is divided into 6 congruent triangles, it simply means that each triangle is an "equilateral" triangle, as you state in the question, or all 3 of its side are equal to each other. Since the perimeter of one of these triangles is 39 inches, then each of its sides =39 / 3 = 13 inches. This is also one side of the hexagon. Since a regular hexagon has 6 sides, then its perimeter =6 x 13 = 78 inches.

Guest Nov 6, 2019

edited by
Guest
Nov 6, 2019

#1**+1 **

Best Answer

Since the regular hexagon is divided into 6 congruent triangles, it simply means that each triangle is an "equilateral" triangle, as you state in the question, or all 3 of its side are equal to each other. Since the perimeter of one of these triangles is 39 inches, then each of its sides =39 / 3 = 13 inches. This is also one side of the hexagon. Since a regular hexagon has 6 sides, then its perimeter =6 x 13 = 78 inches.

Guest Nov 6, 2019

edited by
Guest
Nov 6, 2019