If ,
$f(x)=\frac{16}{5+3x}$
what is the value of
$\left[f^{-1}(2)\right]^{-2}$
?
+23245 If the formula is: y = 16 / (5 + 3x) to find the inverse:
1) interchange the x and y values: x = 16 / (5 + 3y)
2) Solve this equation for y: x(5 + 3y) = 16
5 + 3y = 16/x
3y = 16/x - 5
y = ( 16/x - 5 ) / 3
Now, to finish:
3) Substitute 2 for x and reduce:
4) Square that answer:
5) Invert that answer:
