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In the figure shown, $ABCD$ is a square and $\triangle CDE$ is equilateral. What is the degree measure of $\angle CBE$ ?

CPhill · Answer 1 · 2021-02-12T02:07:14

Note that EC = DC = BC

So triangle ECB is isosceles with EC = BC

So angle ECB = angle CBE

And angle ECB = 90 + 60 = 150°

So angle CBE = ( 180 - 150) / 2 = 30 / 2 = 15°