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In the figure shown, $ABCD$ is a square and $\triangle CDE$ is equilateral. What is the degree measure of $\angle CBE$?

 Feb 12, 2021
 #1
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Note that EC  = DC   =   BC

 

So  triangle  ECB is isosceles with EC  = BC

 

So  angle ECB  = angle  CBE

 

And angle  ECB  = 90  + 60  = 150°

 

So  angle  CBE   = (  180  - 150)  / 2  =   30   / 2  =   15°

 

 

cool cool cool

 Feb 12, 2021

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