+0  
 
0
499
3
avatar

Sarah Was trying to figure out her grades for her math course. She only knew the grade of 4 of the tests total she scored a 94, 67, 83, and 93 . If sarah ended up with a grade of 90 , what did she get on the 5th and Final test

 Jan 6, 2016

Best Answer 

 #1
avatar+128570 
+5

Let x be the unknown test grade.....so we have

 

[ 94 + 67 + 83 + 93  + x ]  / 5   = 90      multiply both sides by 5 and simplify

 

 337  + x  =     450        subtract  337 from both sides

 

x =  113

 

 

 

cool cool cool

 Jan 7, 2016
 #1
avatar+128570 
+5
Best Answer

Let x be the unknown test grade.....so we have

 

[ 94 + 67 + 83 + 93  + x ]  / 5   = 90      multiply both sides by 5 and simplify

 

 337  + x  =     450        subtract  337 from both sides

 

x =  113

 

 

 

cool cool cool

CPhill Jan 7, 2016
 #2
avatar
0

[90 X 5] - [ 94+ 67+ 83+ 93]=113??????!!!!!!!!!

I think there is something wrong with your numbers?.

 Jan 7, 2016
 #3
avatar
+5

To do this, you must use the formula for mean backwards. 

Add all values together and divide by # of values.

 

so it would be

 

94+67+83+93+n

_____________        =  90

            5

 

now simplify!!!!!

multiply both sides by 5 so now you have

 

94+67+83+93+n = 450

 

simplify again

 

337+n=450

n=113

 

 

thats your answer... iguess she got extra credit for a score of 113

 Jan 7, 2016

0 Online Users